1. Calculate the magnitude and direction of the electric field 0.50m from a +8.23^-9C point charge.
2. An electric field dipole consists of two equal but unlike charges separated by a distance. Two point charges, q1=+2.3×10^-6C and q2=3.4×10^-6, are separated by 8.9×10^-2m, forming an electric dipole. Find the electric field halfway between the dipole.
1.
"E=\\frac{kq}{r^2}=300~\\frac NC,"
2.
"E=\\frac{4k(q_1+q_2)}{r^2}=26~\\frac{MN}C."
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