Answer to Question #345786 in Electricity and Magnetism for haseeb

Question #345786

The current through a circuit, in which emf of a cell ε = 120V and internal

resistance r = 0.01Ω is connected with load R= 1000Ω, is:

Expert's answer

"I=\\frac{\\varepsilon}{R+r}=120~mA."

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