Answer to Question #112398 in Field Theory for Rishabh

Question

The expression of the magnetic field associated with an electromagnetic wave in 'vacuum is given by
B = (100D) ysin(2 x103t +k
Determine the wave number, frequency and the direction of propagation of the wave, " aand the magnitude and direction of the electric field associated with it.

Answer 1

The wave number is

$$k=\frac{\omega }{c}=\frac{2000}{3\cdot10^8}=6.67\cdot10^{-6}m^{-1}$$

$$f=\frac{2000}{2\pi}=318.3\ Hz$$ $$E=Bc=(100)(3\cdot10^8)=3\cdot10^{10}\frac{V}{m}$$