Answer to Question #163868 in Field Theory for Mary Ann Castillejo

Question

a plane lands at a speed of 68 m/s and slows down at a rate 0f 4 m/s^2. How much runway is needed to stop the plane?

Answer 1

Answer

By applying third equation of motion

$v^2=u^2+2as$

When plane will stop then

$v=0m/s$

Acceleration

$a=-4m/s^2$

Initial velocity

$u=68m/s$

So by putting value

$0^2=68^2-2(4) (s) \\s=\frac{68^2}{8}\\s=578m$

So 578m runway is required.