A golfer wants to drive a golf ball a distance of 310yards (283m). If the 4-wood launches the ball at 21° above the horizontal, what must the initial speed of the ball be in order to achieve the required distance?
Answer
Vertical velocity can be obtain as
"(vsin21\u00b0)t-\\frac{1}{2}(9.8)t=0\\\\\nvsin21\u00b0-4.9t=0\\quad... Eq. 1"
Horizontal velocity can be obtain as
"vcos21\u00b0t=283\\\\t=\\frac{303.1}{v}"
By eq. 1
"0.36v-\\frac{1485.2}{v}=0\\\\v=64.23m\/s"
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