Answer to Question #291844 in Mechanics | Relativity for bookaddict

Question

an object of mass 60 kg is raised 12 m and then released. assuming no losses due to air resistance, what is its velocity two-thirds of the way down?

Answer 1

Answer

Mass of object m=60kg

Raised at height h=12m

So potential energy

U=mgh

$=60\times 9.81\times12\\=7063.2J$

Potential energy at height h'=8m(two-thirds)

$U'=mgh'=60\times9.81\times8$

$\\=4708.8J$

Let kinetic energy is E at this height

Now using energy conservation

$Ui+Ei=Uf+Ef\\7063.2+0=4708.8+E\\E=2354.4J$

So velocity of object

$v=\sqrt{\frac{2E}{m}}\\=\sqrt{\frac{2\times2354.4}{60}}\\=8.86\space m/s$