Two rugby players run towards each other and have an inelastic collision. Given the mass 70 kg and 60 kg respectively, and velocity 3 ms-1 and 4 ms-1. Calculate the final velocity and its direction of the respective players. Discuss how a rugby player’s bone develops if continuously performing the weight bearing exercise using Wolff’s Law and bone remodeling theory.
Answer
inelastic collision so coefficient of restitution e=0
Mass of players
"m_1=70kg\\\\m_2=60kg"
Initial velocity
"u_1=3m\/s\\\\u_2=4m\/s"
Initial momentum
"P_i=m_1u_1+m_2u_2\\\\=-210+240\\\\=30kg-m\/s"
So final velocities of players as below
"v_1=\\frac{P_i}{(m_1+m_2) }\\\\=\\frac{30}{(70+60) }\\\\=0.23m\/s"
And also
"v_2=\\frac{P_i}{(m_1+m_2) }\\\\=\\frac{30}{(70+60) }\\\\=0.23m\/s"
In this process momentum remains constant.
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