Answer to Question #297485 in Mechanics | Relativity for francis

Question

A certain gasoline weighs 46.5 lb/ft3 . What are its mass density, specific volume and specific gravity?

Answer 1

$1 \:\rm lb/ft^3 = 16.018\:kg/m^3$

$\rho=46.5*\rm 16.018\:kg/m^3=745\:kg/m^3$

$1/\rho=1/745\:\rm kg/m^3=0.0013\: m^3/kg$

$\rho/\rho_w=745\:\rm kg/m^3/1000\: kg/m^3=0.745$