A clock showing correct time when at a rest loses 1 hour when it is moving.what is velocity
Given:
"\\Delta t=24\\rm \\: hr"
"\\Delta \\tau=23\\rm \\: hr"
The time delay equation says
"\\Delta t=\\frac{\\Delta \\tau}{\\sqrt{1-v^2\/c^2}}"So, the required velocity
"v=c\\sqrt{1-(\\Delta \\tau\/\\Delta t)^2}""v=c\\sqrt{1-(23\/24)^2}=0.29c"
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