Answer to Question #299714 in Mechanics | Relativity for Darling Pusta

Question

Given, Sketch, And Solution of the problem?

Answer 1

Answer

Range of object projected at an angle θ

$R=\frac{v^2\sin2\theta}{g}$

Now putting angle of 30° and 50°

So range becomes

$R=\frac{400^2\sin2\times30°}{9.81}=14140m$

And

$R=\frac{400^2\sin2\times50°}{9.81}=16080m$