A man drives a car a distance of 200km at an average speed of 44km/hr what must be his average speed for the next 220km if he is to cover the total distance in 9 hours
The total time of motion
"t=t_1+t_2=\\frac{d_1}{v_1}+\\frac{d_2}{v_2}"Hence
"\\frac{200}{44}+\\frac{220}{v_2}=9""v_2=49.4\\:\\rm km\/hr"
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