Answer to Question #319633 in Mechanics | Relativity for goatboss3023

Question

On your cousin’s wedding day you leave for the church 45.0 min before the ceremony is to begins, which should leave plenty of time since the church is only 30.0 km away.On the way, however, you have to make an unanticipated stop because of road construction work.As a result, your average speed for the first 15 min is only 10.0 km/h.

What average speed do you need to have on the remainder of the trip to get you to the church on time

Answer 1

$s_1=v_1t_1=2.5~km,$

$s_2=s-s_1=27.5~km,$

$t_2=t-t_1=30~min,$

$v_2=\frac{s_2}{t_2}=55~\frac{km}h.$