Answer to Question #320914 in Mechanics | Relativity for HAZELNUY

Question

A 2.0 N, 2.0m long uniform rod is used to suspend various weights. A 2N weight is suspended on one end (point A) and a 5N weight is suspended on the other end (point B). A 2.0N object is suspended 0.5 m from point A and a 1.0N is hanged 0.8 m from point B. How far from the center of the rod shall a 3N weight be placed to balance the rod?*

Answer 1

$x=\frac{F_1l_1+F_2l_2-0 .5F_3l_3}{F_1+F_2}=0.6~m.$