If 5L of a gas is at 1.08 atm . Supposing the volume was 10L what will the volume be at a standard temperature
"p_1V_1=p_2V_2,"
"p_2=p_1\\frac{V_1}{V_2},"
"p_2=1.08\\cdot \\frac{5}{10}=0.54~atm."
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