Answer to Question #270992 in Molecular Physics | Thermodynamics for Maheshi

Question

A hot filament radiates 1.50 W of light. The filament has a surface area of 0.250 mm2

and an emissivity of 0.950. what is the temperature (in kelvin) of the filament?

Answer 1

$$1.5=(0.95)(5.67\cdot10^{-8})(0.25\cdot10^{-6})T^4\\T=3249\ K$$