Answer to Question #317494 in Molecular Physics | Thermodynamics for rajitaofeek

Question

A certain resistance thermometer reads 14.5 Ω in pure melting ice and 18.5 Ω in steam at standard atmospheric pressure. What will be its resistance at room temperature of 27.0oC?

Answer 1

$$R(t_1)=R_0(1+\alpha t_1)\\ R(t_2)=R_0(1+\alpha t_2)$$ $$R(27{^\circ C})=14.5\left(1+\frac{27}{100}*(18.5/14.5-1)\right)\\ =15.6\:\Omega$$