Answer to Question #155438 in Optics for Afraid

Question #155438

Beamwidth (between first nulls) will be for an antenna at 3 MHz with directivity of 100

Expert's answer

Find the beamwidth:

"B=\\frac{140\\lambda}{D}=\\frac{140c}{100f}=\\frac{140\\cdot3\\cdot10^8}{100\\cdot3\\cdot10^6}=140\u00b0."

Learn more about our help with Assignments: Optics

Comments

No comments. Be the first!

Leave a comment

Related Questions

1. An optical fibre is made of glass with a refractive index of 1.55 and is cladwith another glass with
2. One-dimensional crystal assembled from three identical atoms connected to one another and to the wal
3. Consider a cavity consisting of two plane mirrors separated by a distance 60 cm in air. Calculate t
4. Consider a wavelength multiplexer made fromcirculators and fiber Bragg gratings. Assume theinput opt
5. Draw a ray diagram to show a wave bending towards the normal. Mark the angles of incident and refrac
6. plain wavefront of light of wavelength 8800 A° is incedent on two slites in a screen perpendicular
7. Polarization of a wave isA. direction of electric fieldB. direction of magnetic field at some fixed