The critical angle for total internal reflection for sapphire surrounded by air is 34.4 degree. Calculate the polarizing angle for sapphire.
Answer
For critical angle for total internal reflection
"\\frac{n_s}{n_a}=\\frac{sin90^\u00b0}{sin\\theta_c}"
Where s for sapphire and a for air
"n_s=\\frac{1}{sin\\theta_c}=\\frac{1}{sin34.4^\u00b0}"
Now polarization angle
"\\theta_p=\\tan^{-1}(\\frac{n_s}{n_a}) \\\\=\\tan^{-1}(\\frac{n_s}{1}) \\\\=\\tan^{-1}(\\frac{1}{sin34.4^\u00b0}) \\\\=60.5^\u00b0"
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