The image of a real object in a diverging lens of focal length 10cm is formed 4cm from the lens. Find the object distance and the magnification. Draw a sketch to illustrate the formation of the image.
Answer
f=10cm
v=4cm
"\\frac{1}{v}+\\frac{1}{u}=\\frac{1}{f}"
the object distance
"=>u=\\frac{vf}{v-f}\\\\=\\frac{4\\times(10)}{4-20}\\\\=-2.5cm"
the magnification
"m=\\frac{v}{u}=\\frac{4}{-2.5}=-1.6"
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