object is placed in front of a diverging lens with a focal length of 6 CM. Find the image distance for an object distance of 9 cm. Answer in units of cm.
Solution:-
given
u = - 9 cm
f = -6 cm
lens formula
"\\frac{1}{v} - \\frac{1}{u}=\\frac{1}{f}"
"\\frac{1}{v} =\\frac{1}{u}+\\frac{1}{f}"
Putting values
"\\frac{1}{v} =\\frac{1}{-9}+\\frac{1}{-6}"
"\\frac{1}{v} =\\frac{-2-3}{18}"
"\\boxed{V = {-18\\over 5}cm}" i.e image distance
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