The radius of the fifth zone of a zone plate is 2 mm. Considering the zone plate as
a converging lens, calculate its focal length for light of wavelength 4800 Å.
Answer
Given data in question
"r_5=0.002m"
n=5
"\\lambda=4800\\times10^{-10}m"
Thus, the focal length of the zone plate,
"f =\\frac{ r_n^2}{n\\lambda}\\\\=\n\\frac{ (0.002)^2}{5\\times 4800\\times10^{-10} }\n\\\\=166.67m"
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