A car is at a distance 20 m in front of a convex car-mirror having a focal length f = -0.125 m. If the height of the car is 1.45 m, how tall is its image?
h = 0.95 cm
h=1.51 cm
h = 0.76 cm
h = 0.90 cm
h=1.01 cm
Object distance, "u=-20\\space m"
Focal length of car, "f=-0.125\\space m"
Height of object, "h=1.45\\space m"
Height of image "=h'"
Image distance "= v"
"\\dfrac{1}{f}=\\dfrac{1}{v}+\\dfrac{1}{u}"
"\\dfrac{1}{v}=-\\dfrac{1}{0.125}+\\dfrac{1}{20}"
"v=-\\dfrac{4}{3}\\space m"
Magnification, "m=\\dfrac{h'}{h}=-\\dfrac{v}{u}"
"h'=h\\times\\dfrac{-v}{u}"
"h'=-0.09666\\space m\\approx0.95\\space cm"
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