The number of atoms of chlorine present in 5.85g of Nacl is ?( Na =23 Cl=35.5)(Avogadro's number=6.02*10
Answer
The number of atoms of chloride present in 5.85g of NaCl is
"5.85 *6.02 * 10\n^{23}\n= 35.22*10^{23}atoms"
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment