A 1.5 N stone is thrown vertically upward with an
initial speed of 15 m/s . Calculate
a. P.E at the maximum height
b. K.E at the instant it will strike the ground
c. P.E after 1 s
d. K.E after 1 s
(a)
"PE_{\\max}=KE_i=\\frac{mv_i^2}{2}=\\frac{1.5*15^2}{2*9.8}=17.2\\:\\rm J"(b)
"KE_f=KE_i=17.2\\:\\rm J"(c)
"PE=mgh=Wh=W(v_it-gt^2\/2)\\\\\n1.5*(15*1-9.8*1^2\/2)=15.2\\:\\rm J"(d)
"KE=KE_i-PE=17.2-15.2=5\\:\\rm J"
Comments
Leave a comment