Answer to Question #319344 in Physics for Yusuf

Question

A spring is stretched 40mm by a force of 15N. What is the work done by the force

Answer 1

The work done by the force

$$W=\frac{kx^2}{2}=\frac{Fx}{2}\\ =\frac{15\:\rm N*0.04\;\rm m}{2}=0.3\:\rm J$$