Answer to Question #321267 in Physics for Seo

Question

A 300 uF capacitor separated by a distance of 4.0 mm was charged to a potential difference of 250 V. What is the energy density in its region in terms of Joules/m³?

Answer 1

$$\omega=\frac{W}{V}=\frac{CV^2}{2V}=\frac{\epsilon_0V^2}{2d^2}$$

$$=\frac{8.85*10^{-12}*250^2}{2*0.004^2}=0.017\:\rm J/m^3$$