a capacitor that has air between its plates is connected across a potential differences of 12.0 v and stores 48.0 mu c. what is the capacitance of capacitor?
The capacitance
"C=\\frac{q}{V}=\\rm\\frac{48.0*10^{-6}\\:C}{12.0\\: V}=4.00*10^{-6}\\: F=4.00\\: \\mu F"
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