Answer to Question #343448 in Physics for mary

Question

An electric field with a strength of 1.25x104N/C exerted 2.50 N on a

certain test charge, q. Determine the charge on q.

Answer 1

$$F=qE$$

$$q=\frac{F}{E}=\frac{2.50}{1.25*10^4}=2.00*10^{-4}\:\rm C$$