Answer to Question #343714 in Physics for romeo

Question

A force 0f 100 N is directed north on a -20 µC point charge. What is the magnitude and direction of the electric field at this point?

Answer 1

$$F=qE$$

$$E=\frac{F}{q}=\frac{100\:\rm N}{20*10^{-6}\:\rm N/C}=5*10^6\:\rm N$$

The direction of the electric field at this point is toward south.