Answer to Question #348950 in Physics for Tem

Question #348950

A truck travelling at 22.5m/ decelerates at 2.27m/s².

How far does it travel during the third second when brakes are applied?

Expert's answer

"d(t)=v_0t+at^2\/2"

"d=d(3)-d(2)\\\\\n=(v_0*3+a*3^2\/2)-(v_0*2+a*2^2\/2)\\\\\n=v_0*1+5a*1^2\/2\\\\\n=22.5+5*(-2.27\/2)=16.8\\;\\rm m"

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