Let us consider the circular motion of electron, so the acceleration is
"a =\\dfrac{v^2}{r}." The force due to which the motion exists is "F = \\dfrac{1}{4\\pi\\varepsilon_0}\\cdot\\dfrac{e^2}{r^2}." Therefore, "v^2 = \\dfrac{e^2}{4\\pi\\varepsilon_0m_er}."
The angular momentum is "L=m_evr ."
If "L \\gg h," or "L^2\\gg h^2, \\;\\;\\; m_e^2v^2r^2 \\gg h^2, \\;\\;\\; m_e^2\\cdot \\dfrac{e^2}{4\\pi\\varepsilon_0m_er}\\cdot r^2 \\gg h^2, \\;\\;\\; r \\gg \\dfrac{h^24\\pi\\varepsilon_0}{m_ee^2}" .
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