Solution
Here according to question semi major axis a=R/2
Hence "\\tau" is the time of fall then
"(\\frac{2\\tau}{T}) ^2=(\\frac{R\/2}{R}) ^3"
By using kepler third law.
So it's become
"\\tau^2=\\frac{T}{32}"
"\\tau=\\frac{365}{4\\sqrt{2}}=64.5" days
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