Answer to Question #285340 in C for lintik

Question

3. Float Count-off

Counting off a list of float numbers is hard when you speak it, but not when you code it! Don't believe me? Then let's try coding just that!

Instructions:

1. An array containing 30 predefined float values are already provided for you in the code editor. Print each of the element out in separate lines, starting from the last array element down to the first.
2. Each outputted value must also only show up to two decimal places.

Output

Multiple lines containing a float number.

2.41
143.00
3.14
3.12
0.00
-321.12
-414.12
12312.10
4.10
2.42
.
.
.

Answer 1

#include<stdio.h>  


int main(){
	float numbers[]={2.41,143.00,3.14,3.12,0.00,-321.12,-414.12,12312.10,4.10,2.42,
		2.41,143.00,3.14,3.12,0.00,-321.12,-414.12,12312.10,4.10,2.42,2.41,143.00,
		3.14,3.12,0.00,-321.12,-414.12,12312.10,4.10,2.42};
	int i;


	for(i=0;i<30;i++){
		printf("%.2f\n",numbers[i]); 
	}


	
	


	getchar();
	getchar();
	return 0;  
}