Answer to Question #302804 in C for Thank you!

Question

Input number of rows: 2

Input number of columns: 2

Input value of row 0 and column 0:

Input value of row 0 and column 1:

Input value of row 1 and column 0:

Input value of row 1 and column 1:

SUMMARY:

The sum of column 1 is...

The sum of column 2 is...

The difference of column 1 is ...

The product of column is 1 ....

The smallest element in column 1 is .....

Answer 1

#include <stdio.h>
#define N 100
#define M 100


int main() {
    int n, m;
    int arr[N][M];
    int i, j;
    int sum, dif, prod, small;


    printf("Input number of rows: ");
    scanf("%d", &n);
    printf("Input number of columns: ");
    scanf("%d", &m);


    for (i=0; i<n; i++) {
        for (j=0; j<m; j++) {
            printf("Input value of row %d and column %d: ", i, j);
            scanf("%d", &arr[i][j]);
        }
    }


    printf("SUMMARY:\n");
    for (j=0; j<m; j++) {
        sum = 0;
        for (i=0; i<n; i++) {
            sum += arr[i][j];
        }
        printf("The sum of column %d is %d\n", j+1, sum);
    }
    dif = arr[0][0];
    for (i=1; i<n; i++) {
        dif -= arr[0][i];
    }
    printf("The difference of column 1 is %d\n", dif);
    prod = arr[0][0];
    for (i=1; i<n; i++) {
        prod *= arr[0][i];
    }
    printf("The product of column 1 is %d\n", prod);
    small = arr[0][0];
    for (i=1; i<n; i++) {
        if (arr[0][i]<small) {
            small = arr[0][i];
        }
    }
    printf("The smallest element in column 1 is %d\n", small);


    return 0;
}