Answer to Question #311223 in C for Duke

Question

What's in There?

by CodeChum Admin

Let's try defining the size of the array and create the contents of it on our own! And then, to give off a sense of excitement, let's try accessing the value of an array element in a random index position!

Let's do this fast!

Instructions:

1. Create an empty character array with a size of 100.
2. Use an appropriate input function for strings and store the value into the empty array.
3. Input a random integer. It shall only be any integer that's less than the string's length.
4. Using your understanding on accessing list elements, access and print out the array element having the index position of the inputted random integer

Input

1. A string

2. An index

Output

The first line will contain a message prompt to input the string.

The second line will contain a message prompt to input the integer which represents the index.

The last line contains the character at the index.

Enter·the·string:·Cody
Enter·the·index:·3
Character·at·index·3·=·y

Answer 1

#include <stdio.h>






int main()
{
	//Create an empty character array with a size of 100.
	char string[100];
	int index;
	printf("Enter the string: ");
	gets(string);
	//Use an appropriate input function for strings and store the value into the empty array.
	//Input a random integer. It shall only be any integer that's less than the string's length.
	printf("Enter the index: ");
	scanf("%d",&index);
	//Using your understanding on accessing list elements, access and print out the array element 
	//having the index position of the inputted random integer
	printf("Character at index %d = %c",index,string[index]);


	scanf("%d", &index);
	return 0;
}