Answer to Question #345276 in C++ for Ali

Question

Looping problem:

Multiply a number with the sum of its digits.

Answer 1

#include <iostream>


using namespace std;
int sumOfDigits(int number){
    int sum = 0;
    while(number>9){    // if more than 1 digit
        sum+=number%10; // add the last digit
        number/=10;     // get rid of the last digit
    }
    sum+= number;  // add the only digit left
    return sum;
}
int main()
{
    int n;
    cout<<"Enter number: ";
    cin>>n;
    cout<< n*sumOfDigits(n);
    
    return 0;
}