Answer to Question #303757 in MatLAB for Cynthia

Question

A ball is thrown vertically upwards with an initial velocity of 30 m/s.

Using a time step of 0.02 s up to 6.20 s, write a matlab code to give a plot of the vertical distance versus 

time for this ball.

Hint ; Motion under gravity is described by the equation : 𝑣𝑦 = 𝑣𝑜𝑦𝑡 +1/2𝑔𝑡²

and gravitational acceleration 𝑔 is here taken as negative.

Answer 1

close all,
clear all,
clc,

%{
    A ball is thrown vertically upwards with an initial velocity of 30 m/s.
    Using a time step of 0.02 s up to 6.20 s, 
    write a matlab code to give a plot of the vertical distance versus 
    time for this ball.
    Hint ; Motion under gravity is described by the equation :Sy = V0y t + (1/2)gt^2
    and gravitational acceleration g is here taken as negative.
%}


V0 =30; %m/s, Initial Velocity
t = 0:0.02:6.20;    %Time Step
g = 9.8;    %Gravity g in m/sec^2
S = [];
for r=1:length(t)
    S(r) = V0 - ((1/2)*g*t(r)*t(r));
end
scrsz = get(0,'ScreenSize');
Dim=0;
figure('Position',[scrsz(1)+Dim, scrsz(2)+Dim,scrsz(3)-20,scrsz(4)-100]);
plot(t,S,'r');
grid on,
xlabel('--- Time(t) --->');
ylabel('--- Vertical Distance (meters) --->');
title('Plot: Vertical Distance vs time','FontSize',20);