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{"ops":[{"insert":"Rob is fond of collecting coins but unfortunately,sometimes he has to sell a coin to get other coins.he puts all his coins one over the other in a column.\n(0,i):Add coin with value i to the collection.\n(1,0):sell a coin.\nSelling a coin:For selling a coin ,he picks up the top coin in the coloumn if he constraint A is satisfied.Constraint A:Rob can only sell the coin if the coin collection value is more than Y.\nUpon removal ,the coin collection value goes to the previous value.Initially,with 0 coins ,coin collection value is 0.\nAdding a Coin:on adding a coin of value i to the collection the coin collection value increments via the following prodcedure.\nIf the coin collection had>=X value then current total value is X+i else X+2*i.\nRob needs to find and return the final value of coin collection after Q operations.\nNote:Initially,the value X is 0 and not X.\nEx1:\ni\/p1:10(deciding increment)\ni\/p2:0(selling coins)\ni\/p3:1(no of operations)\ni\/p4:{{0,5}}\no\/p:10\n\n"}]}

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