For the reaction
E0r=EO(Ox1/Red1)-EO(Ox2/Red2)
-Eor=E0ox-E0red
E0r(H2/Fe3+)=+0,77-(-0,41)=1,18 V
E(H2S/O2)=+0,822-(-0,22)=-1,042V
E(CH4/NO3-)=+0,75-(-0,24)=0,99V
E(H2/O2)=0,822-(-0,41)=1,232V
E(Fe2+/O2)=0,822-0,77-=0.052V
E(H2S/NO3-)=+0.75-(-0.22)=0,97V
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