Determine the [H+] , [OH−] , and pH of a solution with a pOH of 2.81 at 25 °C.
[H+]=Â
[OH−]=Â
pH=Â
"[H^+]= 10^{-pH}=10^{-(14-pOH)}=10^{-11.19}=6.46*10^{-12}M"
"[OH^-]= 10^{-pOH}=10^{-2.81}=1.55*10^{-3}M"
"pH=14-pOH=11.19"
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