Answer to Question #349059 in Calculus for Mapula Advice

Question #349059

Convert (3–√,−1) into polar coordinates (r,θ) so that r≥0 and 0≤θ<2π.

1
Expert's answer
2022-06-13T23:24:36-0400
"r^2=(-\\sqrt{3})^2+(-1)^2=4""r\\ge0=>r=\\sqrt{4}=2"

Quadrant III


"\\tan \\theta=\\dfrac{-1}{-\\sqrt{3}}=\\dfrac{1}{\\sqrt{3}}""\\theta=\\pi+\\tan^{-1}(\\dfrac{1}{\\sqrt{3}})=\\dfrac{7\\pi}{6}""z_1=2(\\cos\\dfrac{7\\pi}{6}+i\\sin\\dfrac{7\\pi}{6})"




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