Answer to Question #306802 in Field Theory for isay

Question #306802

Find the magnitude of an electron's electric field if the field itself is 50cm away from it.

Expert's answer

The electric field

"E=k\\frac{q}{r^2}\\\\\n=9*10^9*\\frac{1.6*10^{-19}}{0.5^2}=5.76*10^{-9}\\:\\rm V\/m"

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