Answer to Question #337266 in Optics for chan

Question

Light that is nonpolarized has an intensity of 6.0 W/m^2. Rays of this light are incident on two polarizing elements whose transmission axes are at an angle of 45°. What is the intensity of light emerging from the second film?

a. Given:

b. Formula:

c. Solution:

d. Final answer with unit:

Answer 1

a.

$I_0=6~\frac W{m^2},\\ \theta=45°.$

b.

$I=I_0\cos^2\theta.$

c.

$I=6\cdot(\frac{\sqrt 2 }{2})^2=3.$

d.

$3~\frac W{m^2}.$