How many grams of NO will be produced, if 1.93g of H2O are also produced in the reaction below? Show the solution?
4NH3 + 5O2 -----> 4NO + 6H2O
Mr (NO) = 30 g/mol;
Mr (H2O) = 18 g/mol.
4NH3 + 5O2 = 4NO + 6H2O
According to the above reaction, 6 mol (108 g) of H2O is formed when 4 mol (120 g) of NO is formed. We find how many grams of NO are formed when 1,93 g of H2O are formed:
120g NO — 108g H2O
X — 1,93g H2O
X = 120 * 1,93 / 108 = 2,144 g
ANSWER: 2,144 g NO
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