Answer to Question #266864 in Physical Chemistry for jaya

Question

a substance was exposed to radiation of wavelength 4.2x10^-6 m^-1 ;if the frequency difference between the first stokes line and the first anti stokes line is 7.6x10^4 m^-1, calculate the frequencies of two lines.

Answer 1

wavelength $=4.2×10^{-6} m^{-1}$

$Frequency =\frac {1}{T}$ Or $\frac{velocity }{wavelength }$

Velocity $= (4.2×10^{-6})× (7.6×10^4 )= 0.3192$