Answer to Question #324287 in Physical Chemistry for HRMSCA

Question

Calculate the standard enthalpy of formation per mole of ZnS(s).

ZnS(s) + O2(g) → ZnO(s) + SO2(g) ΔH = −878.2 kJ

ΔH_fo(ZnO(s)) = −348.3 kJ/mol

ΔH_fo (SO2(g)) = −296.8 kJ/mol

Answer 1

Standard enthalpy of formation per mole of ZnS(s)=233.1kJ/mol