Answer to Question #315408 in Chemistry for sael

Question

At what temperature will 0.731 moles of neon gas occupy 10.30 L at 2.50 atm? Use the equation: MM= ρRTP

Answer 1

Solution:

n = 0.731 mol

P = 2.50 atm

V = 10.30 L

R = universal gas constant = 0.0821 L atm K⁻¹ mol⁻¹

T = ???

Ideal gas law can be used:

PV = nRT

To find the temperature, solve the equation for T:

T = PV / nR

T = (2.50 atm × 10.30 L) / (0.731 mol × 0.0821 L atm K⁻¹ mol⁻¹) = 429 K

T = 429 K = 156^∘C

Answer: at 429 K