Calculate the hydroxide ion concentration at 25 in a solution whose pH is 5.78. (kW=1*10_14moldm at25)
Solution:
hydroxide ion = [OH−]
pH = −log[H3O+]
Therefore,
[H3O+] = 10−pH = 10−5.78 = 1.66×10−6
[H3O+] = 1.66×10−6 M
Kw = [H3O+] × [OH−]
Therefore,
[OH−] = Kw / [H3O+] = (1.0×10−14) / (1.66×10−6) = 6.02×10−9
[OH−] = 6.02×10−9 M
Answer: The hydroxide ion (OH−) concentration is 6.02×10−9 M
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