Answer to Question #299232 in Algebra for Philly

Question

A straight line passes through the points (2; -3) and (4 - 4). The coordinate of the x intercept of this line is ?

Answer 1

Solution:

Given points (2; -3) and (4, - 4).

Equation of line: $y-y_1=(\dfrac{y_2-y_1}{x_2-x1})(x-x_1)$

$\Rightarrow y+3=(\dfrac{-4+3}{4-2})(x-2) \\\Rightarrow y+3=(\dfrac{-1}{2})(x-2) \\\Rightarrow 2y+6=2-x$

For x-intercept, put y=0

$\Rightarrow 0+6=2-x \\\Rightarrow x=2-6 \\\Rightarrow x=-4$

x-intercept is (-4, 0).