Find ππ¦ ππ₯ if π₯ 2π¦ + 2π¦ 3 = 3π₯ + 2π¦
"x\u00b2y+2y\u00b3=3x+2y"
"2xy+x\u00b2\\frac{dy}{dx}+6y\u00b2\\frac{dy}{dx}=3+2\\frac{dy}{dx}"
"x\u00b2\\frac{dy}{dx}+6y\u00b2\\frac{dy}{dx}-2\\frac{dy}{dx}=-2xy+3"
"(x\u00b2+6y\u00b2-2)\\frac{dy}{dx}=3-2xy"
"\\frac{dy}{dx}=\\frac{3-2xy}{x\u00b2+6y\u00b2-2}"
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